Question

Решите уравнение 2x^2-1999x+1997=0

Answer 1

 

$<var>2x^2-1999x+1997=0\\\\ x_1*x_2 = \frac{1997}{2}\\\\ x_1+x_2 = \frac{1999}{2} = \frac{1997+2}{2} = \frac{1997}{2} + 1\\\\ x_1 = \frac{1997}{2}\\\\ x_2 = 1 </var>$

 

Answer 2

2x^2-1999x+1997=0

D=3996001-4*2*1997=3980025.Dбольше0

x1=(1999-1995)\4=1

x1=(1999+1995)\4=998.5