Question

(x^-3*y^4/9)^2*(3/x-2y3)^-3

номер 144 (2)

Answer 1

$= ( frac{ y^{4}}{9 x^{3} } )^{-2}*( frac{3 x^{2}}{y^{3}} )^{-3} = frac{81 x^{6}}{ y^{8}} * frac{ y^{9}}{9 x^{6}} = 9y$