Question

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log^4(log16^2)

Answer 1

$log_4{left(log_{16}2right)}=log_4{left(log_{2^4}2right)}=log_4{left(frac{1}{4}log_{2}2right)}=log_4{left(frac{1}{4}cdot1right)}=\\=log_4{frac{1}{4}}=log_44^{-1}=-1log_44=-1cdot1=-1.$