Question

1.y=x^2-3
y=(x-3)^2
y=-(x-3)^2


2.(7/6+3целых4/9)*4,5

Answer 1

y=x^2-3 х^2-3=0 х^2=3 х=-√3, √3 y=(x-3)^2 у=х^2-9 х^2-9=0 х^2=9 х=-+3 y=-(x-3)^2 х^2-9=0 х=-+3