Question

$frac{1}{x} - frac{x+6y}{6xy}$
x=√32
y=$frac{1}{9}$

Answer 1

$frac{1}{x}- frac{x+6y}{6xy} = frac{1*6y}{x*6y}- frac{x+6y}{6xy} = frac{6y}{6xy}- frac{x+6y}{6xy} = frac{6y-(x+6y)}{6xy}= frac{6y-x-6y}{6xy}=$
$= frac{-x+6y-6y}{6xy}= frac{-x}{6xy}=- frac{1*x}{6*x*y} =- frac{1}{6*y} =- frac{1}{6y} =-1:(6y)=$
$=-1:(6* frac{1}{9} )=-1: frac{6*1}{9} =-1: frac{2*3}{3*3}=-1: frac{2}{3}=-1* frac{3}{2}=-1*1.5=$
$=-1.5=- frac{3}{2}$