Question

/////Решите плиз ^^ ///////////

Answer 1

$frac{x^2-y^2}{xy}:frac{x-y}{3y}cdotfrac{1}{x+y}=frac{(x-y)(x+y)}{xy}cdotfrac{3y}{x-y}cdotfrac{1}{x+y}=\\=frac{(x-y)(x+y)cdot3y}{xycdot(x-y)(x+y)}=frac{3y}{xy}=frac{3}{x}.$

Answer 2

Рад помочь