Предмет: Химия, автор: ahmetova1gulka

Рассчитайте объём воздуха необходимого для сжигания 100 л (н.у.) пропана

Ответы

Автор ответа: Sanek252med

0

C3H8 + 5O2 = 3CO2 + 4H2O

количество пропана v=V/Vm=100/22,4=4,4643 моль

количество воздуха по уравнению реакции v=5*4,463=22,315 моль

объем кислорода V=22,315*22,4≈500 моль,

содержание кислорода в воздухе 21%,

тогда объем воздуха V=500/0,21= 2381 л

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