Question

Пожалуйста,сократите дробь!

Answer 1

$frac{7x^2+x-8}{7x-7}= frac{7x^2-7x+8x-8}{7*x-7*1}= frac{(7x*x-7x*1)+(8*x-8*1)}{7*(x-1)}=$
$= frac{7x*(x-1)+8*(x-1)}{7*(x-1)}= frac{(7x+8)*(x-1)}{7*(x-1)}= frac{7x+8}{7} = frac{7x}{7} + frac{8}{7}= x+ frac{8}{7}$