Question

срочно: 54/ sin(-34pi/3)*cos(35pi/6)

Answer 1

sin(-34π/3)=sin(-33π/3-π/3)=sin(-11π-π/3)=sin(-10π-π-π/3)=sin(-π-π/3)=-sin(π+π/3)=-(-sin π/3)=sin π/3=√3/2

cos(35π/6)=cos(30π/6+5π/6)=cos(5π+5π/6)=cos(4π+π+5π/6)=cos(π+5π/6)=-cos5π/6=-√3/2

54/(√3/2)*(-√3/2)=-54