Question

Вычислите предел функции по бесконечности

Answer 1

$lim_{x to 3} frac{x^3 - 27}{x-3} = lim_{x to 3} frac{(x-3)(x^2+3x+9)}{x-3} = lim_{x to 3} x^2 + 3x + 9 = 27 \ lim_{x to infty} frac{5x}{3x-1} = 5/3 \ lim_{x to infty} frac{3x^2 - 4x + 7}{2x^2 - 5x + 6} = 3/2$