Question

Помогите расписать, пожалуйста :с

Answer 1

$frac{x^2+6x}{x-2} leq 0 \ left { {{x(x+6) leq 0} atop {x-2 textless 0}} right. \ left { {{x_1 leq 0, x_2 leq -6} atop {x textless 2}} right.$
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$frac{x(x+1)}{x-9} textgreater 0 \ left { {{x(x+1) geq 0} atop {x-9 textgreater 0}} right. \ left { {{x_1 geq 0, x_2 geq -1} atop {x textgreater 9}} right.$
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$frac{3x-2}{2x-3} textgreater 3 \ frac{3x-2}{2x-3}-3 textgreater 0 \ frac{3x-2-3*(2x-3)}{2x-3} textgreater 0 \ left { {{3x-2-6x+9 geq 0} atop {2x-3 textgreater 0}} right. \ left { {{-6x geq -7} atop {2x-3 textgreater 0}} right. \ left { {{x geq 1 frac{1}{6} } atop {x textgreater 1,5}} right.$
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$frac{x+3}{x-2} textless 1 \ frac{x+3-x+2}{x-2} textless 0 \ left { {{0x textless 5} atop {x textless 2}} right.$
Решений не имеет.
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$x^2+6x+9 geq 0 \ (x+3)^2 geq 0 \ x geq 3, x geq -3$
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$-4x^2+20x textgreater 25 \ -4x^2+20x-25 textgreater 0 \ 4x^2-20x+25 textgreater 0 \ (2x-5)^2 textgreater 0 \ x textgreater 2,5$

Answer 2

Спасибо)