Question

Вирішіть будь-ласка. Буду вдячна))

Answer 1

$frac{5}{7} (7x-2)+ frac{1}{7}(2-7x)+3= frac{5}{7}*7x- frac{5}{7}*2+ frac{1}{7}*2+ frac{1}{7}*(-7x)+3=$
$= frac{5*7*x}{7*1}- frac{5*2}{7}+ frac{1*2}{7}- frac{1*7*x}{1*1*7}+3= = frac{5*x}{1}- frac{10}{7}+ frac{2}{7}- frac{x}{1}+3=$
$= 5x+ frac{-10+2}{7}-x+3 = 5x-x+ frac{-8}{7}+3 = 4x- frac{8}{7}+3=$
$= 4* frac{3}{4} - frac{8}{7}+3= frac{4*3}{4*1} - frac{8}{7} +3= frac{3}{1} - frac{1+7}{7} +3= 6 -1- frac{1}{7}=$
$=5- frac{1}{7}=4 frac{6}{7}$