Question

(c^2+100)/(c-10) + (20c)/(10-c)
Упростите выражение

Answer 1

$frac{c^{2}+100}{c-10}+ frac{20c}{10-c}= frac{c^{2}+100}{c-10}- frac{20c}{c-10}= frac{c^{2}+100-20c}{c-10}= frac{c^{2}-20c+100}{c-10}=\ =frac{(c-10)^{2}}{c-10}=c-10$