Question

3у^2-7у-10больше0, помните скорей

Answer 1

$3y^2-7y-10 textgreater 0,\\3y^2-7y-10=0,\D=7^2-4bullet3bullet(-10)=49+120=169,\x_{1,2}=frac{7pmsqrt{169}}{2bullet3}=frac{7pm13}{6},\x_1=frac{7+13}{6}=frac{20}{6}=frac{10}{3}=3frac{1}{3},\x_2=frac{7-13}{6}=frac{-6}{6}=-1.\\a=3 textgreater 0 to x textless -1, x textgreater 3frac{1}{3}.\\OTBET: x textless -1, x textgreater 3frac{1}{3}.$