Question

Решите пожалуйста)
a) p(p+7)>7p-1
б) 8y(3y-10)<(5y-8)^2
в) (a-3)(a-5)<(a-4)^2
г) f(x) = -5x+6
f(x)= -3
f(0)= 0

Answer 1

$a) p(p+7) textgreater 7p-1,\p^2+7p textgreater 7p-1,\p^2+7p-7p+1 textgreater 0,\p^2+1 textgreater 0,\p^2 textgreater -1,\pin mathh {R};\\b) 8y(3y-10) textless (5y-8)^2,\24y^2-80y textless 25y^2-80y+64,\-y^2 textless 64,\y^2 textgreater -64,\yin mathh {R};\\c) (a-3)(a-5) textless (a-4)^2,\a^2-5a-3a+15 textless a^2-8a+16,\15 textless 16,\ain mathh {R};\\d) f(x)=-5x+6,\f(x)=-3,\-5x+6=-3,\-5x=-9,\x=frac{9}{5}=1frac{4}{5}=1.8,\f(1.8)=-3;\f(0)=-5bullet0+6=6,\f(0)=6.$

Answer 2

Я бетмен