Question

Решите пожалуйста!
2x-1/1-x^2 <-1

Answer 1

ОДЗ
1-х²=0
(1-х)(1+х)=0
х=1
х=-1

$- frac{2(x-0.5)}{ x^{2} -1} textless -1 \ frac{2(x-0.5)}{ x^{2} -1} textgreater 1 \ frac{2(x-0.5)}{ x^{2} -1}-1 textgreater 0 \ frac{2x-1- x^{2} +1}{(x-1)(x+1)} textgreater 0 \ frac{x(2- x)}{(x-1)(x+1)} textgreater 0 \ frac{x(x-2)}{(x-1)(x+1)} textless 0$

x∈(-∞; -1)∨[0; 1)∨[2; +∞)