Question

Помогите пожалуйста!

Answer 1

N20)  1)a³-2a²-2a+4=a²(a-2)-2(a-2)=(a-2)(a²-2)²
   2)= (x³+6x²)-(2x+12)=x²(x+6)-2(x+6)=(x+6)(x²-2)
  3)=(c^4-2c²)+(c³-2c)=c²²(c²-2)+c(c²-2)=(c²+c)(c²-2)=c(c+1)(c²-2)
  4) =-y^5(y+1)+y³(y+1)=(y+1)(y³-y^5)=y³(y+1)(1-y²)