Предмет: Алгебра, автор: fjjkjh

Запишите в виде дроби
А)n+2/n!-3n+2/(n+1)!
Б)1/(k-1)!-k/(k+1)
В)1/(k-2)!-k^3+k/(k+1)!

Ответы

Автор ответа: sedinalana
0
А
(n+2)/n!-(3n+2)/(n+1)! =(n+2)/n!-(3n+2)/[n!(n+1)]=
=(n²+n+2n+2-3n-2)/[n!(n+1)]=n²/(n+1)!
Б
1/(k-1)!-k/(k+1)!=1/(k-1)!-k/[(k-1)!*k*(n+1)]=
=(k²+k-k)/(k+1)!=k²/(k+1)!
В
1/(k-2)!-(k^3+k)/(k+1)! =1/(k-2)!-(k³+k)/[(k-2)!(k-1)k(k+1)]=
=(k³-k-k³-k)/(k+1)!=-2k/(k+1)!
Автор ответа: fjjkjh
0
I never not boring with my friends
Автор ответа: fjjkjh
0
Friends help us express ourselves because we spend time together and like the same things and so we are not afraid to express our opinions with them. I've experienced a lot with my friends because I've known them for a long time and we have done a lot together.
Автор ответа: fjjkjh
0
I'm never bored with my friends as we often go out together, go to mall or hang out at a cafe. Sometimes we just chat about everything and play board games in my house.
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