Question

sin(x-П/3)=-1/2 тригонометрия

Answer 1

sin(x-П/3)=-sin(П/3-x)=-sin(П/2-(П/6+x))=-cos(x+П/6)=-1/2
cos(x+П/6)=1/2
x+П/6=+-П/3+2пk
x=П/3-П/6+2пk=п/6+2Пk
x=-П/3-п/6+2Пk=-П/2+2Пk, k∈Z