Question

Решите систему уравнений {x^2-3y=9
{x-y=3

Answer 1

x = 3+y

(3+y)^2 - 3y = 9
9 + 6y +y^2 - 3y = 9
y^2 +3y = 0
y = 0
y=-3

x-0=3
x=3

x+3 = 3
x=0

(0;-3) (3;0)