Question

решите задачу по химии 9 класс

Answer 1

Mr (Al2S3)=27*2+32*3=54+96=150 г/моль
W(Al) = 2$frac{Ar(Al)*k}{Mr(Al2S3)*100} = frac{27*2}{150}*100=36%$

W(S) = $frac{32*3}{150}*100=64%$

ω(Al) = 2$frac{Ar(Al)*k}{Mr(Al2S3)*100} = frac{27*2}{150}*100=36%$

ω(S) = $frac{32*3}{150}*100=64%$

2m(Al) : 3m(S) = 2*27 : 3*32 = 54 : 96