Question

0,36х^4-25/9у^6 плзплз

Answer 1

$0,36y^4- frac{25}{9} y^6=(0.6)^2*y^4- frac{(5)^2}{(3)^2}*y^2*y^4 =y^4*[(0.6)^2- (frac{5}{3})^2y^2 ]=$
$=y^4*[( frac{3}{5} )^2- (frac{5}{3})^2y^2 ]=y^4*[( frac{3}{5} )^2*(frac{5}{3} )^2*( frac{3}{5} )^2- (frac{5}{3})^2y^2 ]=$
$=(frac{5}{3} )^2y^4*[( frac{3}{5} )^2*( frac{3}{5} )^2-y^2] =(frac{5}{3} )^2y^4*[(( frac{3}{5} )^2)^2-y^2]=$
$=(frac{5}{3} )^2y^4*[(( frac{3}{5} )^2)^2-(y)^2]=(frac{5}{3} )^2y^4[( frac{3}{5} )^2-y]*[( frac{3}{5} )^2+y]=$
$=(frac{5}{3} )^2y^4[ 0.36-y]*[0.36+y]$