Question

сократить дробь x^3-3x^2+x-3/2x^3-x^2+2x-1

Answer 1

$frac{ x^3-3x^2+x-3}{2x^3-x^2+2x-1}=frac{x^2(x-3)+(x-3)}{x^2(2x-1)+(2x-1)}=frac{(x-3)(x^2+1)}{(2x-1)(x^2+1)}=frac{x-3}{2x-1}$

Answer 2

x^3-3x^2+x-3/2x^3-x^2+2x-1=x^2*(x-3)+(x-3)/x^2*(2x-1)+(2x-1)=(x-3)(x^2+1)/(2x-1)(x^2+1)=x-3/2x-1