Question

ЗАДАЧА ПО МЕХАНИКЕ!!!!!!!!!!!!!!!!!!!!

Answer 1

Rx = -F₁·sin 30° - F₃·cos 45° = -4·1/2 - 2·√2/2 = -2 - √2 ≈ -3,41 кН Ry = F₁·cos 30° + F₂ - F₃·sin 45° = 4·√3/2 + 2 - 2·√2/2 = 2√3 + 2 - √2 ≈ 4,05 кН R = $\sqrt{Rx^2+Ry^2}=\sqrt{(-3,41)^2+4,05^2}$ ≈ 5,3 кН