Question

Разложите на множители:
-1+49a^4b^8

Answer 1

$-1+49a^4b^8=7^2(a^2)^2(b^4)^2-1^2=(7a^2b^4)^2-(1)^2=$
$[7a^2b^4-1]*[7a^2b^4+1]=[( sqrt{7} ab^2)^2-1]*[7a^2b^4+1]=$
$=[ sqrt{7} ab^2-1]*[ sqrt{7} ab^2+1]*[7a^2b^4+1].$