Question

1. limx^2-9:x-3 x>3
2. lim x-3: корень х+1 и -2 х>3
3. lim x^2=x-6:x-2 x>2
помогитее

Answer 1

$lim_{x to 3} frac{ x^{2} -9}{x-3} = frac{ 3^{2}-9 }{3-3} =[ frac{0}{0} ]$
$lim_{x to 3} frac{ x^{2} -9}{x-3} = lim_{x to 3} frac{(x-3)*(x+3)}{x-3} = lim_{x to 3} (x+3)=3+3=6$

$lim_{x to 3} frac{x-3}{ sqrt{x+1}-2 } =[ frac{0}{0}]$
$lim_{x to 3} frac{(x-3)*( sqrt{x+1}-2)}{( sqrt{x+1}-2 )*( sqrt{x+1}+2 )} = lim_{x to 3} frac{(x-3)*( sqrt{x+1}-2 )}{( sqrt{x+1} ) ^{2}-2^{2} } =$
$= lim_{x to 3} frac{(x-3)*( sqrt{x+1}+2) }{x-3} = lim_{x to 3} ( sqrt{x+1} +2)= sqrt{3+1}+2 =4$

Answer 2

Спасииибочки