Question

пожалуйста помогите срочно нужно

Answer 1

(x²-y²)(x²+y²)/(x³+yx²)-(xy²+y³) -2y= ((x-y)(x+y)(x²+y²))/ (x²(x+y)-y²(x+y)) -2y=
  =((x-y)(x+y)(x²+y²))/ ((x²-y²)(x+y) -2y =x²+y²)/(x+y) -2y=(x²+y²-2y(x+y))/(x+y)=   (x²+y²-2xy-2y²)/x+y=x²-y²-2xy)/x+y