Question

Помогите пожалуйста!

Answer 1

$1) frac{(10x^4y ^{-3})^4}{16x^8(25x^2y^{-2})^3}= frac{10^4x^{16}y^{-12}}{16x^825^3x^6y^{-6}} = frac{10^4x^2y^{-6}}{16*25^3} = frac{(5*2)^4x^2y^{-6}}{2^4*5^6} = \ \ =frac{5^42^4x^2y^{-6}}{2^4*5^6} = 5^{-2}x^2y^{-6}= frac{x^2}{25y^6} \ \ 2) sqrt{72} +(3- sqrt{2} )^2- sqrt[4]{81} = \ \ sqrt{4*2*9} +9-6 sqrt{2}+2 - sqrt[4]{3^4} =6sqrt{2} +9-6 sqrt{2} +2-3= 8 \ \ 3) x^{3} -3 x^{2} -4x+12=0 \ x^{2} (x-3)-4(x-3)=0 \ \ (x-3)(x^2-4)=0 \ (x-3)(x-2)(x+2)=0$
$x=3\x=2\x=-2 \ OTBET:3; 2; -2$