Question

РЕШИТЕ СИСТЕМУ {x^2+y^2-10=0 {xy-3=0

Answer 1

$displaystyle left { {{x^2+y^2-10=0} atop {xy-3=0}} right. \\ left { {{(x+y)^2-2xy-10=0} atop {xy=3} right.\\(x+y)^2-6-10=0\(x+y)^2=16\\ left { {{x+y=pm 4} atop {yx=3}} right. \\x_1=1;y_1=3\x_2=3;y_2=1\x_3=-1;y_3=-3\x_4=-3;y_4=-1$