Question

10+(3x-1)^2=20-6x алгебра

Answer 1

$10+(3x-1)^2=20-6x\ 10+9x^2-6x+1=20-6x\ 9x^2+11-20=0\ 9x^2-9=0\ 9(x^2-1)=0\ x^2-1=(x-1)(x+1)=0\ x+1=0rightarrow x_1=-1}\ x-1=0rightarrow x_2=1$