Question

((2x^2)^9-(2x^3)^6)/16 x^18

Answer 1

$frac{(2x^2)^9-(2x^3)^6}{16x^{18}}=frac{2^9x^{18}-2^6x^{18}}{16x^{18}}=frac{2^6x^{18}(2^3-1)}{16x^{18}}=2^2*7=28$