Question

((2x^2)^9-(2x^3)^6)/16 x^18

Answer 1

$frac{(2x^2)^9-(2x^3)^6}{16x^{18}}= frac{2^9x^{18}-2^6x^{18}}{2^4x^{18}}= frac{2^9x^{18}(2^3-1)}{2^4x^{18}}=2^2cdot2^3-2^2=4cdot8-4=28$