Question

7-а 3 9а(квадрат) - 1
____ - ____ * ___________
5а-2 3а-1. 5а- 2

Срочно!!!!

Answer 1

$frac{7-a}{5a-2}-frac{3}{3a-1}*frac{9a^2-1}{5a-2}=frac{7-a}{5a-2}-frac{3}{1}*frac{3a+1}{5a-2}=frac{7-a-9a-3}{5a-2}=\frac{4-10a}{5a-2}=frac{-2(-2+5a)}{5a-2}=-2$