Question

Помогите решить уравнение! Срочно!
1) (2x-3)^2 - (7-2x)^2 = 2

Answer 1

$(2x-3)^2-(7-2x)^2=2\\ (2x-3)^2-(2x-7)^2=2\\ (2x-3)^2-(2x-3-4)^2=2\\ 2x-3=t\\ t^2-(t-4)^2=2\\ t^2-(t^2-8t+16)=2\\ 8t-16=2\\ 8t=18\\ t= frac{9}{4}\\ 2x-3= frac{9}{4}\\ 2x= frac{21}{4}\\ x= frac{21}{8}$