Question

Решите уравнение
(х-2)²+8х = (х-1)(1+х)

Answer 1

$(x-2)^2+8x=(x-1)(1+x) \ \ x^2-2*x*2+2^2+8x=x^2-1^2 \ \ x^2-4x+4+8x=x^2-1 \ \ x^2+4x-x^2=-1-4 \ \ 4x=-5 \ \ x=-5:4 \ \ x=- frac{5}{4} \ \ x=-1 frac{1}{4} \ \ x=1,25$