Question

преобразуйте в многочлен выражение -(x+2)^2-(x-3)*(x+4)

Answer 1

 -хв2-4х-4-хв2-4х+3х+12=

-2хв2-5х+8

Answer 2

$-(x+2)^2-(x-3)*(x+4)=\ \ = -(x^2+4x+4)-(x^2-3x+4x-12) = \ \ = -(x^2+4x+4)-(x^2-x-12)= \ \= -x^2-4x-4-x^2+x+12=-2x^2-3x+8$