Question

помоогите (3cos π x-π)(2sin π x-√3)=0

Answer 1

[3cosπx=π⇒cosπx=π/3>1 нет решения
{2sinπx=√3⇒sinπx=√3/2⇒πx=(-1)^n*π/3+πn⇒x=(-1)^n*1/3+n<n∈z

Answer 2

cosπx = π/3 > 0

sinπx = √3/2

πx = π/3 + 2πn
πx = 2π/3 + 2πk

x = 1/3 + 2n
x = 2/3 + 2k

n,k - целые