Question

(4c+3y)/(c^2-y^2)-3/(c-y)

Answer 1

(4с+3y)/[(с-y)(с+y])-3/(с-y)=(4c+3y-3c-3y)/(c²-y²)=c/(c²-y²)

Answer 2

$frac{4c+3y}{ c^{2} - y^{2} } - frac{3}{c-y} = frac{4c+3y}{ c^{2} - y^{2} } - frac{3(c+y)}{(c-y)(c+y)} = frac{4c+3y}{ c^{2} - y^{2} } - frac{3c+3y}{ c^{2} - y^{2} } = frac{4c+3y-3c-3y}{ c^{2} - y^{2} } = \ = frac{c}{ c^{2} - y^{2} }$