Question

СРОЧНО ПОМОЩЬ С УРАВНЕНИЯМИ:
1) (1/3x-2)^3-x^5-18x^4
-------------- = 4
27x^2
2) x^6-24x^5
--------------- -(1/2x-4)^3=4
8x^3
3)(y+4)^3-(y+8)^2
--------------------- = -1
y^2

Answer 1

1.(1/3x-2)³- (x^5-18x^4)/27x²=4
x≠0
x³/27-4x²/9+4x/3-2x²/9+8x/3-8-x³/27+2x²/3-4=0
12x/3-12=0
x=3
2.( x^6-24x^5)/8x³- (x/2-4)³=4
    x≠0
  x³/8 -3x²- x³/8+2x²-8x+x²-16x+64-4=0
  -24x+60=0
    x=5/2
3.( (y+4)³-(3y+8)²)/y² +1=0
    y≠0
  (y³+8y²+16y+4y²+32y+64-9y²-48y-64+y²)/y²=0
   y³+4y² =0
    y=-4