Question

1- If 0.2mol of an alkane weighs 8.8g, what is its molecular formula? (C3H8)

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Answer 1

M(CxHy) = m/n   M=8,8g/0,2mol = 44g/mol

 

alkan  CnH₂n₊₂

12n+2n+2 =44

14n =42

n=3

 

C3H8     C₃H₈