Question

Решить уравнение.
3( -0,5 +2x^2 - (x+2)(2x-4)) = 5x-20

Answer 1

$3(-0,5+2x^2-(x+2)(2x-4))=5x-20\3(-0,5+2x^2-(x+2)(x-2)2)=5(x-4)\frac{3(-0,5+2x^2-2(x^2-4))}{5}=frac{5(x-4)}{5}\0,6(-0,5+2x^2-2x^2+8)=x-4\0,6*7,5+4=x\x=8,5$