Question

(x-6)^2+5(x-3)^2+9=(3x-1)^2-3(x+2)^2-19

Answer 1

$(x-6)^2+5(x-3)^2+9=(3x-1)^2-3(x+2)^2-19\x^2-12x+36+5(x-3)^2+9=(3x-1)^2-3(x+2)^2-19\x^2-12x+5(x^2-6x+9)=9x^2-6x+1-3(x^2+4x+4)-64\-8x^2-6x+5x^2-30x+45=-3x^2-12x-12-63\-24x=-120\x=5$