Question

(6X+2)^2+7x=4(3x-1)+55

Answer 1

(6x+2)^2+7x=4(3x-1)^2+55(36х^2+24х+4)+7х=4(9х^2-6х+1)+55
36х^2+24х+4+7х=36х^2-24х+4+55
24х+7х+24х=4+55-4
55х=55
Ответ: х=1

Answer 2

$(6x+2)^2+7x=4(3x-1)^2+55\36x^2+24x+4+7x=4(9x^2-6x+1)+55\36x^2+31x=36x^2-24x+4+51\55x=55\x=1$