Question

построить линию заданную уравнением 2|x-1|+3|y-2|=6

Answer 1

$2|x-1|+3|y-2|=6, \ x-1=0, x=1, \ y-2=0, \ y=2, \ 1) x textless 1, y textless 2; \ 2(1-x)+3(2-y)=6, \ 2-2x+6-3y=6, \ -2x-3y+2=0; \ begin{array}{c|cc}x&-2&4\y=-frac{2}{3}x+frac{2}{3}&2&-2end{array} \ 2) x textless 1, y textgreater 2; \ 2(1-x)+3(y-2)=6, \ 2-2x+3y-6=6, \ -2x+3y-10=0, \ begin{array}{c|cc}x&-2&1\y=frac{2}{3}x+frac{10}{3}&2&4end{array} \ 3) x textgreater 1, y textgreater 2; \ 2(x-1)+3(y-2)=6, \ 2x-2+3y-6=6, \ 2x+3y-14=0, \ begin{array}{c|cc}x&-2&1\y=-frac{2}{3}x+frac{14}{3}&6&4end{array}$
$4) x textgreater 1, y textless 2; \ 2(x-1)+3(2-y)=6, \2x-2+6-3y=6, \ 2x-3y-2=0, \ begin{array}{c|cc}x&-2&4\y=frac{2}{3}x-frac{2}{3}&-2&2end{array}$

Answer 2

крсавчик:D