Question

Алгебра.
Задание, решить уравнение.

Answer 1

$frac{4y+24}{5y^2-45} + frac{y+3}{5y^2-15y} = frac{y-3}{y^2+3y} \\ frac{4y+24}{5(y-3)(y+3)} + frac{y+3}{5y(y-3)} = frac{y-3}{y(y+3)} \\ frac{(4y+24)y+(y+3)^2-5(y-3)^2}{5y(y-3)(y+3)} =0\\ frac{4y^2+24y+y^2+6y+9-5y^2+30y-45}{5y(y-3)(y+3)} =0\\ frac{60y-36}{5y(y-3)(y+3)} =0; ,; ; ODZ:; yne 0,; yne -3,; yne 3\\60y=36\\10y=6\\y=frac{6}{10}\\y=frac{3}{5}$