Question

Решите неравенство: log1/6(4x − 32) > log1/6(3x).

Answer 1

$log_{frac{1}{6}}(4x-32) textgreater log_{frac{1}{6}}3x\0 textless frac{1}{6} textless 1to\left{{{4x-32 textless 3x}atop{4x-32 textgreater 0}}right.left{{{4x-3x textless 32}atop{4x textgreater 32}}right.left{{{x textless 32}atop{x textgreater 8}}right.\8 textless x textless 32$
Ответ: x∈(8; 32)