Question

(44а²вс³)*(2ас)*(3ав³)/6а²в³с=
(m-n)^2+(m+n)²/2m=

Answer 1

$frac{44a^2bc^3cdot 2accdot 3ab^3}{6a^2b^3c} = frac{44, a^4b^4c^4}{a^2b^3c} =44, a^2bc^3\\ frac{(m-n)^2+(m+n)^2}{2m} = frac{m^2-2mn+n^2+m^2+2mn+n^2}{2m} = frac{2(m^2+n^2)}{2m} = frac{m^2+n^2}{m}$