Question

Упростить выражение номер ж

Answer 1

$frac{(x^2+y(x+y))(x^2-y^2)(x+y)^2}{(x^3+3xy(x+y)+y^3)(x^3-y^3)} = \ \ = frac{(x^2+xy +y^2)(x-y)(x+y)(x+y)(x+y)}{(x^3+3x^2y +3xy^2+y^3)(x^3-y^3)} = \ \ = frac{(x^3-y^3)(x+y)^3}{(x+y)^3(x^3-y^3)} = frac{1}{1} =1$