Предмет: Физика, автор: Litlle228

ПОМОГИТЕ ,ОЧ НАДО,ДАЮ МНОГО БАЛЛОВ

Имеются два бруска: медный и алюминиевый. Объем одного из этих брусков на 50 см 3 больше, чем объем другого, а масса на 175 г меньше массы другого. Каковы объемы и массы брусков?

Ответы

Автор ответа: Utem
0
Используем формулу плотности
ρ=m/V
для нахождения массы
m₁=ρ₁V₁ - масса меди
m₂=ρ₂V₂ - масса алюминия
Пусть объём меди V₁=V, а масса меди m₁=m, тогда объём алюминия V₂=V-50 см³, а масса алюминия m₂=m+175 г
ρ₁=8,9 г/см³ - плотность меди
ρ₂=2,7 г/см³ - плотность алюминия
V*8,9=(V+50)*2,7+175
8,9V=2,7V-135+175
8,9V-2,7V=40
6,2V=40
V=40:6,2≈6,4516 см³ - объем меди
V₂=6,4516+50=56,4516 см³ - объём алюминия
m=8,9*6,4516=57,4192 г. - масса меди
m₂=2,7*56,4516=152,4193 г. - масса алюминия



Автор ответа: Litlle228
0
не то
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