Question

15с-10с^2=
х^2-25=
16-с^2=
а^2-6а+9=
1+2у+у^2=
а^3-8=
27+а^3=
2а^2-8в^2

Answer 1

$15c-10c^2=5c(3-2c)\\x^2-25=(x-5)(x+5)\\16-c^2=(4-c)(4+c)\\a^2-6a+9=(a-3)^2=(a-3)(a-3)\\1+2y+y^2=(1+y)^2=(1+y)(1+y)\\a^3-8=(a-2)(a^2+2a+4)\\27+a^3=(3+a)(9-3a+a^2)\\2a^2-8b^2=2(a^2-4b^2)=2(a-2b)(a+2b)$